today = datetime.date.today() first = datetime.date(day=1, month=today.month, year=today.year) lastMonth = first - datetime.timedelta(days=1) print lastMonth.strftime("%Y%m")

http://stackoverflow.com/questions/9724906/python-date-of-the-previous-month

>>> import datetime >>> today = datetime.date.today() >>> print(today) 2018-08-24 >>> yesterday = today - datetime.timedelta(days=1) >>> print(yesterday) 2018-08-23 >>> 06.02.14 today = datetime.datetime.now().strftime('%Y%m%d') yearback = (datetime.datetime.now() - datetime.timedelta(days=1*365)).strftime('%Y%m%d') 06.02.14

https://stackoverflow.com/questions/5158160/python-get-datetime-for-3-years-ago-today

default one year back for a fastapi function from datetime import datetime, date, timedelta async def styles_sold(self,date: str = (datetime.now() - timedelta(days=1*365)).strftime('%Y%m%d')): 06.02.14

• Home
• Notebook
• Contact us

• Privacy Statement
• 

Copyleft ☠ 2025