How to convert a String into a str in rust22.02.23

You cannot obtain &'static str from a String because Strings may not live for the entire life of your program, and that's what &'static lifetime means. You can only get a slice parameterized by String own lifetime from it.

To go from a String to a slice &'a str you can use slicing syntax:

let s: String = "abcdefg".to_owned();
let s_slice: &str = &s[..];  // take a full slice of the string

Alternatively, you can use the fact that String implements Deref<Target=str> and perform an explicit reborrowing:

let s_slice: &str = &*s;  // s  : String 
                          // *s : str (via Deref<Target=str>)
                          // &*s: &str

There is even another way which allows for even more concise syntax but it can only be used if the compiler is able to determine the desired target type (e.g. in function arguments or explicitly typed variable bindings). It is called deref coercion and it allows using just & operator, and the compiler will automatically insert an appropriate amount of *s based on the context:

let s_slice: &str = &s;  // okay

fn take_name(name: &str) { ... }
take_name(&s);           // okay as well

let not_correct = &s;    // this will give &String, not &str,
                         // because the compiler does not know
                         // that you want a &str

https://stackoverflow.com/questions/23975391/how-to-convert-a-string-into-a-static-str

Anonymous

How to convert a String into a str in rust22.02.23

Information Epoch 1722051070