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Find duplicated in mssql
28.10.17
SELECT [av0_style], COUNT(*) AS dupes FROM [SL].[dbo].[zz_free_displays] GROUP BY [av0_style] HAVING (COUNT(*) > 1)
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Anonymous
drop table #dub SELECT [mh2_code_price_list] ,[mh2_style_code] ,[mh2_from_qty] ,ROW_NUMBER() OVER(PARTITION by [mh2_code_price_list] ,[mh2_style_code] ,[mh2_from_qty] ORDER BY [mh2_code_price_list]) AS counting INTO #dub FROM[mh2_price_list_ln2] select * from #dub
28.10.17
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Anonymous
Information Epoch 1762687114
Solving the next 5% probably costs more than the previous 90%.
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